### Discussion :: References - Programs (Q.No.14)

Rajendra Mahanor said: (Sep 20, 2014) | |

enum started value a=0, b=1, c=3 then, Assign value x=a=0, y=b=1, z=c=2 then, Reference value, &p = x = 0. &q = y = 1. &r = z = 2. Now p=z means p=2 again p=++q pre-increment &q=y=1, p=++q=2. Then, q = ++p = 3. After q=4. z = ++q+p++. z = 3+4. z = 7. p = 4. So output is p=4, q=4 and z=7. |

Amarnath said: (Sep 20, 2014) | |

We can't change(++, --) enum values. |

Bidyut said: (Mar 6, 2017) | |

How a, b, c are given values? |

Pritha said: (Sep 17, 2017) | |

How can we assign the values of a, b, c in such a random manner? |

Abhinav said: (Jan 14, 2018) | |

Explain it. |

Manimegalai said: (Apr 20, 2018) | |

Please, anybody explain it. |

Vishal Singh said: (Jun 17, 2018) | |

It's the property of enum that they are initialized from 0 and stay in sequential increment order (i.e. A=0, b=1, c=2), also by enum property we can't change the value of enum after initialization. |

Tavish said: (Aug 10, 2019) | |

How can we random assigned the values to a b and c. |

Minu said: (Nov 29, 2019) | |

P=z=2. P=++q=++1=2. Q=++p=++2=3. Z=++q+p++ Z=4+3=7. Q=4. P=3++=4. |

Sandesh said: (May 20, 2020) | |

How q==4? Please anyone explain it. |

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